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Daily Math Minute

Unit 2: Differentiation — Definition & Fundamental Properties

Power & Sum Rules

Differentiating using the power rule and sum/difference rules.

Advanced25 min lesson3 min readUpdated August 12, 2026Author not yet attributed

Prerequisites

  • Differentiability & Continuity

A Shortcut, Derived from the Definition

Computing f'(x) = 2x for f(x) = x² from the limit definition took several algebra steps. Before reading on: is there a pattern in that result — 2x from x², matching '2 times x to the power one less than 2' — that might generalize to any power of x?

The pattern does generalize, and it isn't a coincidence — it falls straight out of the same difference-quotient process. For f(x) = x³, expand (x + h)³ = x³ + 3x²h + 3xh² + h³ using the binomial expansion. Then [f(x+h) − f(x)]/h = (3x²h + 3xh² + h³)/h = 3x² + 3xh + h², and as h → 0, every remaining term with a factor of h vanishes, leaving exactly 3x² — matching '3 times x to the power one less than 3.' The same binomial-expansion argument works for any positive integer power n: every cross term in (x + h)ⁿ carries at least one factor of h except the leading nxⁿ⁻¹h term, so dividing by h and letting h → 0 always leaves n·xⁿ⁻¹.

Definition — Power, Constant Multiple, and Sum/Difference Rules

For any real exponent n, d/dx[xⁿ] = n·xⁿ⁻¹. Constants factor out of a derivative: d/dx[c·f(x)] = c·f'(x). And derivatives distribute over sums and differences: d/dx[f(x) ± g(x)] = f'(x) ± g'(x).
ddx[xn]=nxn1\frac{d}{dx}\big[x^n\big] = n\,x^{n-1}

Worked Example — Differentiating a Polynomial

Differentiate f(x) = 4x⁵ − 3x² + 7x − 2. Apply the power rule term by term: d/dx[4x⁵] = 20x⁴, d/dx[−3x²] = −6x, d/dx[7x] = 7, and d/dx[−2] = 0 (a constant's rate of change is always 0). So f'(x) = 20x⁴ − 6x + 7.

Worked Example — Rewriting Radicals and Fractions as Powers First

Differentiate g(x) = 3√x + 5/x². Rewrite as g(x) = 3x^(1/2) + 5x^(−2) before applying the power rule. g'(x) = 3 · (1/2)x^(−1/2) + 5 · (−2)x^(−3) = (3/2)x^(−1/2) − 10x^(−3), which can be rewritten back as g'(x) = 3/(2√x) − 10/x³.

Derivative Explorer

Point of tangency
1

f(x), with tangent line at x = a

Derivative graph — linked to the graph above; panning or zooming either moves both

What's happening at x = a
  1. At x = 1, f(x) ≈ -2 — the point (1, -2).
  2. The derivative there is f'(1) ≈ 0: the slope of the tangent line, and the instantaneous rate of change of f at this exact point.
  3. That slope is positive, so f is increasing at this point.
  4. The second derivative is positive here, so f is concave up (curving upward) near this point.
  5. Near x = 1, the tangent line y ≈ -2 + 0·(x − 1) is f's best straight-line approximation — the core idea a derivative captures.
Numerical derivative comparison
Forward, backward, and central difference estimates of f'(a) as the step size h shrinks — all three should converge toward the same value.
hForwardBackwardCentral
14-21
0.10.31-0.290.01
0.010.0301-0.02990.0001
0.0010.003-0.0030
Analysis of f(x)
y-intercept
(0, 0)
x-intercepts
(-1.73, 0), (0, 0), (1.73, 0)
Extrema
local max at (-1, 2); local min at (1, -2)
Inflection points
(0, 0)
Vertical asymptotes
none found in view
Horizontal asymptotes
none found
Domain
all real numbers in view
Range (estimated)
approximately [-970, 970]
Analysis of f'(x) — its roots are f's critical points
y-intercept
(0, -3)
x-intercepts
(-1, 0), (1, 0)
Extrema
local min at (0, -3)
Inflection points
none found in view
Vertical asymptotes
none found in view
Horizontal asymptotes
none found
Domain
all real numbers in view
Range (estimated)
approximately [-3, 297]

Tip

Before applying the power rule, rewrite every radical and denominator as a power of x with a fractional or negative exponent — the power rule applies exactly the same way regardless of whether the exponent is a positive integer, a fraction, or negative.

Common Mistakes

  • Applying the power rule to a constant term and getting a nonzero result.

    A constant c can be written as c·x⁰, and the power rule gives c·0·x⁻¹ = 0 — a constant's derivative is always 0, since its rate of change is always 0.

  • Forgetting to reduce the exponent by 1 in the new coefficient, writing d/dx[5x⁻²] as −10x⁻² instead of −10x⁻³.

    The power rule reduces the exponent by exactly 1 regardless of its sign: n = −2 becomes n − 1 = −3, so the correct derivative is 5 · (−2)x^(−2−1) = −10x⁻³.

Key Takeaways

  • d/dx[xⁿ] = n·xⁿ⁻¹ follows directly from the limit definition, via the binomial expansion of (x+h)ⁿ.
  • Constants factor out of derivatives, and derivatives distribute over sums and differences — a polynomial can be differentiated term by term.
  • Rewriting radicals and fractions as powers of x (fractional or negative exponents) lets the power rule handle them directly.

Summary

The power rule handles sums of power terms quickly, but not products or quotients of two whole functions. The next lesson derives rules for exactly that.