Systems of Equations & Inequalities
Systems by Substitution
Solving a system of linear equations using substitution.
Collapsing Two Equations into One
y = 2x + 3 and 3x + 2y = 16 describe two different lines. Before reading on, think about this: since both equations involve y, could you use one equation's expression for y to eliminate y from the other equation entirely — leaving just one equation with one unknown?
That's exactly the idea behind substitution: if y genuinely equals 2x + 3, then everywhere y appears in the second equation, it can be replaced by that expression instead — because they're the same value. Doing this collapses two equations with two unknowns into a single equation with only x left, solvable with tools you already have.
Worked Example — Substituting an Already-Isolated Expression
Worked Example — Solving for a Variable Before Substituting
Worked Example — Recognizing No Solution via Substitution
Tip
Common Mistakes
Substituting an expression into the same equation it came from, instead of into the other equation.
Solve one equation for a variable, then substitute that expression into the other equation — substituting back into the original equation just restates a true but useless statement.
Stopping after finding one variable's value and reporting it alone as the full solution.
A system's solution is a full point, (x, y) — after finding one variable, always substitute it back into an original equation to find the other.
Key Takeaways
- Substitution replaces a variable with an equivalent expression from the other equation, reducing a system to one equation with one unknown.
- A false statement after substitution means the system has no solution — the lines are parallel.
- Substitution works most smoothly when a variable is already isolated, or easily can be.
Summary
Substitution solves a system by collapsing it to a single-variable equation. The next lesson introduces a second algebraic method — elimination — which shines exactly where substitution gets messy.
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