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Daily Math Minute

Unit 4: Contextual Applications of Differentiation

Local Linearization

Using a tangent line to approximate function values near a point.

Advanced25 min lesson3 min readUpdated August 12, 2026Author not yet attributed

Prerequisites

  • Related Rates

Approximating with the Tangent Line

√4 = 2 exactly, but √4.1 has no clean closed form. Before reading on: since 4.1 is so close to 4, could the tangent line to y = √x at x = 4 — a straight line, easy to evaluate anywhere — give a genuinely good estimate of √4.1?

Definition — Local Linearization

The linearization of f at x = a is L(x) = f(a) + f'(a)(x − a) — the equation of the tangent line at a, used to approximate f(x) for x near a. The approximation is exact at x = a itself and grows less accurate the farther x moves away.
L(x)=f(a)+f(a)(xa)L(x) = f(a) + f'(a)(x - a)

Worked Example — Approximating a Square Root

Approximate √4.1 using the linearization of f(x) = √x at a = 4. f(4) = 2, f'(x) = 1/(2√x), f'(4) = 1/4. L(x) = 2 + (1/4)(x − 4). L(4.1) = 2 + (1/4)(0.1) = 2.025. The actual value, √4.1 ≈ 2.024846, is very close — and slightly less than the approximation. That direction isn't an accident: f''(x) = −1/(4x^(3/2)) is negative for x > 0, so f is concave down, meaning its tangent line lies above the curve — a concave-down function's linearization always overestimates nearby.

Worked Example — Approximating a Trig Value (Converting to Radians First)

Approximate cos(61°) using the linearization of f(x) = cos(x) at a = 60° = π/3 radians — calculus derivative formulas for trig functions require radians. f(π/3) = cos(60°) = 0.5, f'(x) = −sin(x), f'(π/3) = −sin(60°) = −√3/2 ≈ −0.8660. The change from 60° to 61° is 1° = π/180 ≈ 0.017453 radians. L = 0.5 + (−0.8660)(0.017453) ≈ 0.48488. The actual value, cos(61°) ≈ 0.48481, is again very close — and again slightly less than the linearization, consistent with cosine also being concave down on this interval (cos''(x) = −cos(x) < 0 for x near 60°).

Derivative Explorer

Point of tangency
1

f(x), with tangent line at x = a

Derivative graph — linked to the graph above; panning or zooming either moves both

What's happening at x = a
  1. At x = 1, f(x) ≈ -2 — the point (1, -2).
  2. The derivative there is f'(1) ≈ 0: the slope of the tangent line, and the instantaneous rate of change of f at this exact point.
  3. That slope is positive, so f is increasing at this point.
  4. The second derivative is positive here, so f is concave up (curving upward) near this point.
  5. Near x = 1, the tangent line y ≈ -2 + 0·(x − 1) is f's best straight-line approximation — the core idea a derivative captures.
Numerical derivative comparison
Forward, backward, and central difference estimates of f'(a) as the step size h shrinks — all three should converge toward the same value.
hForwardBackwardCentral
14-21
0.10.31-0.290.01
0.010.0301-0.02990.0001
0.0010.003-0.0030
Analysis of f(x)
y-intercept
(0, 0)
x-intercepts
(-1.73, 0), (0, 0), (1.73, 0)
Extrema
local max at (-1, 2); local min at (1, -2)
Inflection points
(0, 0)
Vertical asymptotes
none found in view
Horizontal asymptotes
none found
Domain
all real numbers in view
Range (estimated)
approximately [-970, 970]
Analysis of f'(x) — its roots are f's critical points
y-intercept
(0, -3)
x-intercepts
(-1, 0), (1, 0)
Extrema
local min at (0, -3)
Inflection points
none found in view
Vertical asymptotes
none found in view
Horizontal asymptotes
none found
Domain
all real numbers in view
Range (estimated)
approximately [-3, 297]

Tip

Before evaluating a trig linearization, convert the change in input to radians — every calculus derivative formula for sin, cos, and tan assumes a radian input, so a degree-based Δx has to be converted first.

Common Mistakes

  • Using Δx in degrees directly inside a trig linearization instead of converting to radians.

    f'(a) for a trig function is only correct in radians — plugging in Δx = 1 (as if it meant '1 degree') instead of π/180 radians produces a wildly wrong approximation.

  • Trusting a linearization far from the point of tangency without checking how far x has moved.

    Linearization error grows the farther x moves from a — it's reliable very close to a, but the same tangent line can be a poor approximation even a moderate distance away, especially where the function curves sharply.

Key Takeaways

  • Linearization L(x) = f(a) + f'(a)(x − a) approximates f near a using its tangent line at a.
  • A concave-down function's linearization overestimates nearby values; a concave-up function's linearization underestimates them, since the tangent line lies on the opposite side of the curve from its concavity.
  • Trig linearizations require the input change to be in radians, since calculus derivative formulas for trig functions assume radians throughout.

Summary

Linearization approximates function values near a point. The next lesson uses that same tangent-line thinking to resolve a different kind of problem — limits that resist ordinary algebra.